Puzzle 8K35 Main |
| by Richard Pavlicek |
Few people are aware that Pharaoh Amenhotep IV (18th Dynasty) invented the high-card ranks inherent to bridge and other card games. Fortunately, PavCo Historians are here to educate you, so read on.
In the palace of Amenhotep IV were 16 bricks of four different sizes. Etched on each large brick was a circle depicting the sun god Aten; the second largest bricks had etchings of Amenhotep I to IV; the third largest, their four wives; and the smallest, their four sons. These brick ranks evolved into ace, king, queen and jack, as familiar today.
Every year Amenhotep IV would waive taxation to any landowner who could arrange the bricks in a diagram to satisfy his cryptic whim. Below is one such waiver, translated from hieroglyphics:
With shovels in control and southerly instigation, hands along the Nile must
render enemy forces brickless. Landlords, place your bricks! -Amenhotep IV
Pawn layout | 2 | |
Form 1040-A | 3 | |
| ||
| ||
| | |
| 2 | |
3 | | |
2 | 3 | |
3 | ||
| ||
2 | ||
© 1339 BC | |
Since the Nile runs North-South, I interpret the ancient wording to mean:
With spades trump and South to lead, place the 16 high cards (A-K-Q-J) so North-South can win all the tricks.
Many solutions exist. Your goal is to accomplish it with (1) fewest N-S HCP, (2) fewest South HCP, and (3) fewest West HCP, in that order of priority. Further, to qualify as a legal bridge ending, at least three suit holdings must remain void.
Kudos to Tim Broeken, the first solver in the brick yard, as well as the first double winner in this contest series. Do you suppose he bought his bricks at the Yarborough Fair?
Rank | Name | Location | N-S | S | W |
---|---|---|---|---|---|
1 | Tim Broeken | Netherlands | 14 | 5 | 12 |
2 | Zla Khadgar | Ohio | 14 | 5 | 12 |
3 | Charles Blair | Illinois | 14 | 5 | 12 |
4 | Edouard Bonnet | France | 14 | 5 | 12 |
5 | Reint Ostendorf | Netherlands | 14 | 5 | 12 |
6 | Gareth Birdsall | England | 14 | 5 | 12 |
7 | David Brooks | Australia | 14 | 5 | 12 |
8 | Dan Dang | British Columbia | 14 | 5 | 12 |
9 | Audrey Kueh | England | 14 | 5 | 12 |
10 | Jonathan Mestel | England | 14 | 5 | 12 |
11 | Hendrik Nigul | Estonia | 14 | 5 | 12 |
12 | Jonathan Buss | Ontario | 14 | 5 | 12 |
13 | Simon Creasey | England | 14 | 5 | 12 |
14 | Pavel Striz | Czech Republic | 14 | 5 | 12 |
15 | Ufuk Cotuk | England | 14 | 5 | 12 |
16 | Julian Wightwick | England | 14 | 5 | 12 |
17 | James Lawrence | England | 14 | 5 | 12 |
18 | Nick Jacob | New Zealand | 14 | 5 | 12 |
19 | Alberto Gioa | Italy | 14 | 5 | 13 |
20 | Dan Baker | Texas | 14 | 5 | 13 |
21 | Jeffrey Tsang | Pennsylvania | 14 | 5 | 13 |
22 | Jacco Hop | Netherlands | 14 | 8 | 11 |
23 | Radu Vasilescu | Pennsylvania | 14 | 8 | 11 |
24 | John Reardon | England | 14 | 8 | 12 |
25 | Paul Nelson | California | 14 | 8 | 12 |
26 | Thomas Haukland | Norway | 15 | 5 | 10 |
27 | Jon Greiman | Illinois | 15 | 5 | 10 |
28 | Jonathan Ferguson | Texas | 15 | 6 | 12 |
29 | Jim Munday | California | 15 | 7 | 10 |
30 | Colin Schloss | Pennsylvania | 15 | 7 | 10 |
31 | Richard Stein | California | 15 | 8 | 13 |
Puzzle 8K35 Main | Top The Bricks of Amenhotep |
A change of pace, as this amenipotent contest is more like Sudoku than bridge; but then, bridge wasnt invented yet. The Origin of Bridge came 22 years later with Amenhotep IVs son, better known as Tutankhamun. (Not all historians will agree, but thats my story and Im stickin to it.) Indeed, some people were disappointed that the solution was an ordinary crossruff, rather than some amenruffensqueeze. To them, I will point out that were talkin bricks here, not precious gems.
The condition of at least three voids has no bearing on the solution, as any construction with two or fewer voids, besides being illegal* would require more HCP for North-South to win six tricks. For example, with two voids the minimum is 16 HCP.
*Legal endings must be reachable from a full deal without a revoke or other irregularity.
While hardly a necessity for puzzles, especially about bricks, I try to keep things legal so
I might resemble a bridge player at least in a dimly lit room.
The most obvious requirement is that N-S have the A, as even the High Priest of Amun couldnt avoid that loser; further, it should go to North to minimize Souths HCP. The next idea might be to give East-West each a mummy, er stiff, K or Q. Several solvers tried this on early attempts but found improvements, so Ill attribute my first example to Kharis, the most feared mummy of all time:
win 6 | A 2 | Trick | Lead | 2nd | 3rd | 4th | |
K Q J 3 | 1. S | 3 | Q | A | K | ||
| 2. N | K | A | J | 2 | ||
| North wins the rest | ||||||
Q | K | ||||||
| A 2 | ||||||
K 3 | A | ||||||
K Q 2 | A 3 | ||||||
J 3 | |||||||
| |||||||
Q J 2 | |||||||
South leads | J |
The above HCP counts of 15:5:10 for NS:S:W total one point fewer than the winning solution of 14:5:12, but of course lose out in the stipulated priority.
Another way of achieving the 15:5:10 HCP counts is to give North-South all the trumps and minimal HCP elsewhere. Thomas Haukland (Norway) put it all together for a simple crossruff:
win 6 | A K 2 | Trick | Lead | 2nd | 3rd | 4th | |
Q J 3 | 1. S | 2 | 3 | 2 | K | ||
| 2. N | 3 | 2 | 3 | K | ||
| Crossruff the rest | ||||||
| | ||||||
K | A 2 | ||||||
Q 3 | A K | ||||||
K Q 2 | A 3 | ||||||
Q J 3 | |||||||
| |||||||
J 2 | |||||||
South leads | J |
Declarer could even succeed in the above layout if he led a trump to dummy.
Jim Munday: Even Fritz could bring this one home. If I find the correct solution can you waive taxation for me this year?
Of course! Just open an account in PavCo Cayman Bank and youll Pay No Taxes!
In theory, the minimum HCP for N-S is 14, since the A must be held, and the weakest the remaining honors can be is three queens and four jacks. Souths theoretical minimum is 5 HCP, because 4 HCP (four jacks) would mean no void suit, demanding at least 16 HCP for N-S. The remaining high cards dictate Wests theoretical minimum as 11 (three kings and a queen) which, alas, cannot be achieved. West must settle for 12 HCP, as Tim Broeken (Netherlands) shows with his winning entry:
win 6 | A Q 2 | Trick | Lead | 2nd | 3rd | 4th | |
Q J 3 | 1. S | 2 | 3 | 2 | K | ||
| 2. N | 3 | 2 | 3 | K | ||
| 3. S | J | 2 | Q | A | ||
K | | 4. N | J | 3 | J | A | |
A K | 2 | 5. S | Q | ? | |||
3 | A K | Win the rest | |||||
Q 2 | A K 3 | ||||||
J 3 | |||||||
| |||||||
Q J 2 | |||||||
South leads | J |
West has no effective defense as declarer crossruffs. If he pitches a heart on the second diamond preparing to overruff, the North hand becomes high and the last trump is drawn. If he pitches a club (as shown), South safely ruffs a heart to establish the Q. South next leads the good Q, and West can only choose which red queen will win a trick.
Charles Blair: According to Geza Ottlik, West is squeezed in hearts on the second round of diamonds.
I have a theory about this too. The Great Pyramid is located in Giza, which translates to Geza in Hungarian. Trust me, when Ottlik penned Adventures in Card Play, he was high on tana leaves.
The optimal solution (14:5:12) discovered by the top 18 solvers is unique, and so proved by combinatorial exhaustion.
Jonathan Mestel: Ra, Ra, PavCo! I was hoping for a sacred crocodile coup.
Wayne Somerville: How did King Amenhotep manage to get a copyright in 1339 BC? How did they even know it was 1339 BC?
Kharis? An infidel dares to question my veracity, so we have a new mission [Richard prepares the fluid of nine tana leaves]
Puzzle 8K35 Main | Top The Bricks of Amenhotep |
© 2011 Richard Pavlicek